Question

Prove the following Identities for two negative integers are -2 and -3
(a+b)²=a²+2ab+b²​

Answer 1

Solution:

• Numbers are - 2 and -3 as a and b respectively.
• (a+b)²=a²+2ab+b²

LHS = RHS

(a+b)²=a²+2ab+b²

( -2 - 3)² = -2² - 2.-2.-3 + -3²

( -5)² = 4 + 12 + 9

25 = 13 + 12

25 = 25

Hence, It's Proved.

Important Algebraic identities:

→ a³ - b³ = ( a - b)(a²+ ab + b²)

→ a³ + b³ = ( a + b)(a² - ab + b²)

→ a² - b² = (a+b)(a-b)

→ (a+b)² = a² + b² + 2ab

→ (a- b)² = a² + b² - 2ab