Math, asked by hariparsadnayak22, 11 months ago

Prove the following identities:
(SecA+CosA)(SinA-CosA)=tan^2A+sin^2A

Answers

Answered by dhruvkoul

1

Answer:

Step-by-step explanation:

LHS

(1/cosA+cosA)(sinA-cosA)

(1+cos²A/cosA)(sinA-cosA)

sinA+cos²AsinA-cosA-cos³A/cosA

tanA+cosAsinA-1-cos²A

RHS

sin²A+sin²Acos²A/cos²A

tanA+cosAsinA-1-cos²A

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