Prove the following identities :
sin4 A – cos4 A = 2 sin2 A – 1 = 1 – 2 cos2 A = sin2 A – cos2 A
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2Sin3*Sin1 = 2Cos3*Sin1
tan3 = -1
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QUESTION:
prove that
sin⁴A - cos⁴A = 2sin²A - 1 = 1 - 2sin²A = sin²A - cos²A
USED FORMULAS:
(a - b)² = a² - 2ab + b²
a² - b² = (a + b)(a - b)
sin²A + cos²A = 1
sin²A = 1 - cos²A
cos²A = 1 - sin²A
ANSWER:
(sin²A)² - (cos²A)²
= (sin²A + cos²A)(sin²A - cos²A)
= 1(sin²A - cos²A)
= sin²A - cos²A ✓✓
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= sin²A - (1 - sin²A)
= sin²A - 1 + sin²A
= 2sin²A - 1 ✓✓
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= (1 - cos²A) - cos²A
= 1 + cos²A + cos²A
= 1 + 2cos²A ✓✓
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