Prove the following identity :-
(1 - tan A)^2 + (1 + tan A)^2 = 2 sec^2 A
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Answer:
2sec^2A
Step-by-step explanation:
firstly apply the identity (a-b)^2=a^2-2ab+b^2 and
(a+b)^2=a^2+2ab+b^2
so,
equation reduce to
=> (1+tan^2A-2tanA)+(1+tan^2A+2tanA)
=> (1+1+tan^2A+tan^2A+2tanA-2tanA)
=> (2+2tan^A)
now taking common 2
=> 2 (1+tan^2A)
here apply the identity 1+tan^2A=sec^2A
=> 2(sec^2A)
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