prove the following identity...
Attachments:

Answers
Answered by
1
Step-by-step explanation:
it can be simplified and written as
(sinA+sinB)(sinA-sinB) + (cosA+cosB)(cosA-cosB) / (cosA+cosB)(sinA+sinB)
= sin^2A -sin^2B+cos^2A - cos ^B / (cosA+cosB)(sinA+sinB)
= (sin^2A + cos^2 A )- (sin^2B+ cos ^2 B) / (cosA+cosB)(sinA+sinB)
= 1-1/(cosA+cosB)(sinA+sinB)
=0
HOPE IT HELPS SO PLEASE MARK ME BRAINLIEST AND FOLLOW ME
Answered by
1
Answer:
hope it helps !!
mark as brainliest please!!:-)
Attachments:

Similar questions