Question

Prove the following identity​

Answer 1

Answer:

refer to the attachment

hope it helps u ....

Answer 2

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$\sf{LHS = \frac{1}{(secA - 1)} + \frac{1}{(secA + 1)} }$

$\sf{ = [ \frac{secA + 1 + secA - 1}{(secA - 1)(secA + 1)}]}$

$\sf{ = \frac{(2secA)}{( {sec}^{2} A - 1)} }$

$\sf{ = \frac{(2secA)}{ { tan }^{2}A } }$

$\sf{ = \frac{ \frac{2}{cosA} }{ \frac{ {sin}^{2}A }{ {cos}^{2}A } } }$

$\sf{ = \frac{(2cosA)}{ {sin}^{2}A } }$

$\sf{ =2 \frac{1}{sinA} \frac{cosA}{sinA} }$

$\sf{ = 2cosecAcotA}$

$\sf{ = RHS}$

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