Prove the following identity
Attachments:
Answers
Answered by
1
LHS
cosA-sinA+1/CosA+sinA-1
Divide by sinA
cotA-1+CosecA/cotA+1-CosecA
On rearranging
cotA+cosecA-1/cotA-cosecA+1
Using the identity
1+cot2A=cosec2A
cotA+cosecA-(cosec²A-cot²A)/cotA-cosecA+1
cotA+CosecA-[(cosecA+cotA)(cosecA-cotA) ]/cotA-cosecA+1
taking CotA+CosecA common
CotA+CosecA(1-cosecA+CotA)/cotA-CosecA+1
on cancelling the terms we get..
CotA+CosecA=RHS
Hence proved!!
Hope it helps you! please mark me brainliest
Answered by
2
this is the answer for the question. I hope it will help you. please mark my answer is a brianliest
Attachments:
Similar questions