Question

prove the following identity: (a+b)2=a2 +2ab +b2​

Answer 1

Step-by-step explanation:

(a+b)²

= (a+b)×(a+b)

= (a+b)(a+b)

= [a×(a+b)]+[b×(a+b)]

= [a(a+b)]+[b(a+b)]

= [{(a×a)+(a×b)}] + [{(b×a)+(b×b)}]

= [(a²)+(ab)] + [(ba)+(b²)]

= (a²)+(ab)+(ba)+(b²)

Since a×b = b×a (commutative property), ba = ab.

= (a²)+(ab)+(ab)+(b²)

= (a²)+(2×ab)+(b²)

= (a²)+(2ab)+(b²)

Answer 2

Answer:

here is your exaplnation

Step-by-step explanation:

(a+b)^2= (a+b) (a+ b)

= a(a+b) +b ( a+ b)

=a^2+ab + ab+ b^2

=a^2 + 2ab + b^2

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