Question

Prove the following identity:

(given in pic)​

Answer 1

Answer:

$formula \: = \sin{}^{2} + \cos{}^{2} = 1$

Step-by-step explanation:

hope it's help you

Answer 2

Step-by-step explanation:

We have,

$\rm \sin ^2 θ \bigg( \dfrac{1}{1-\cos θ} + \dfrac{1}{1+ \cos θ} \bigg)$

$\rm \sin ^2 θ \bigg\{\dfrac{1+ \cos θ+1-\cos θ}{(1-\cos θ)(1+ \cos θ)} \bigg\}$

$\rm \sin ^2 θ \bigg\{\dfrac{1+ \cancel{\cos θ}+1-\cancel{\cos θ}}{1-\cos ^2θ} \bigg\}$

$\rm \sin ^2 θ \bigg(\dfrac{2}{\sin ^2θ} \bigg)$

$\rm \cancel{\sin ^2 θ} \bigg(\dfrac{2}{\cancel{\sin ^2θ}} \bigg)$

$\rm =2$