Question

Prove the following identity :
(tan 0 + 2)(2 tan 0 + 1) = 5 tan 0 + 2 sec- e
Or​

Answer 1

Step-by-step explanation:

tan0 = 0

therefore L.H.S becomes:

= (0+2)(0+1)

=2

R.H.S:

=5(0) + 2sec(-e)

=2

rhs = LHS

proved