prove the following
please
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Step-by-step explanation:
From ΔAPN and ΔAPM,
PN = PM (given)
angle ANP = angle AMP ( perpendicular 90 degree)
AP = AP ( common side)
By SAS –
ΔAPN ~( congruent) to ΔAPM
Therefore, AP bisects angle MAN
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Answer:
Here it is
Step-by-step explanation:
In triangles MAP and NAP,
Angle AMP=Angle ANP=90°
MP=NP
AP=AP (common side)
So, the two triangles AMP and ANP are congruent through the RHS criterion
Therefore, AP is the bisector of angle MAN
(since Angle MAP=Angle NAP)
(congruent parts of congruent triangles are always equal)
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