prove the following questions
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Step-by-step explanation:
a+ib×c-id +a-ib×c+id/(c+id)(c-id)
ac-aid+ibc-i^2bd +ac+iad-ibc-i^2bd/c^2-i^2d^2
as i^2=-1
and by cancellation we have
ac +2bd +2bd/c^2+d^2
ac+4bd/c^2+d^2 which is also real
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