Question

Prove the following: sec^(4)A-1=2tan^(2)A+tan^(4)A

Answer 1

Step 1: Break 1−sin4A as a2−b2 form.

1−sin4A=(1−sin2A)(1+sin2A)=cos2A(1+sin2A) form.

Step 2: sec4A and cos2A multiplies to form sec2A

L.H.S. = sec2A(1+sin2A)−2tan2A

Step 3: Taking sec2A common

L.H.S. = sec2A1+sin2A−2sin2A=sec2A1−sin2A=sec2Acos2A=1 = R.H.S (Proved)

hope this helps you.

pls mark as brainliest.