Prove the following: sec² θ + cosec² θ = sec² θ x cosec² θ
Prove the following: (sec θ + tan θ) (1 – sin θ) = cos θ
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Step-by-step explanation:
- LHS=sec^2A + cosec^2A
=(1/cos^2A) + (1/sin^2A)
=sin^2A+cos^2A/cos^2A*sin^2A
(by taking LCM)
=1/cos^2A*sin^2A
=1/cos^2A*1/sin^2A
(by taking 1 on both sides)
=sec^2Acosec^2A
(since, 1/cos=sec and
1/sin=cosecA) [ Hence, PROVED ]
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