Math, asked by Anonymous, 11 months ago

Prove the following
sin 2x + 2 sin 4x + sin 6x = 4 cos^2 x sin 4x​

Answers

Answered by ʙʀᴀɪɴʟʏᴡɪᴛᴄh
4

Answer:

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Answered by athira05
0

Answer:

L.H.S. = sin 2 x + 2 sin 4 x + sin 6 x

[sin 2 x + sin 6 x ] + 2 sin 4x

2 sin 4 x cos 2 x + 2 sin 4x

2 sin 4 x cos 2 x + 2 sin 4x

2 sin 4 x (cos 2 x + 1)

2sin4x(2cos x -1+1)

2 sin 4 x (2 cos x )

4cos x sin 4 x

= R.H.S.

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