Prove the following:-
sin^4x + cos^4x+sin^2xcos^2x=( 1-sinxcosx)(1+sinxcosx)
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Step-by-step explanation:
We know that
Sin²x + Cos²x = 1
Doing square both sides
(Sin²x + Cos²x)² = 1
Sin⁴x + Cos⁴x + 2Sin²x*Cos²x = 1
Sin⁴x + Cos⁴x + Sin²x*Cos²x = 1 - Sin²x*Cos²x
Sin⁴x + Cos⁴x + Sin²x * Cos²x
= (1+Sinx*Cosx) (1-Sinx*Cosx)
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