Question

prove the following:
$\sqrt{ \frac{1 + \sin(a) }{1 - \sin(a) } } = \tan(a) + \sec(a)$
THE FIRST ONE TO ANSWER WILL BE MARKED AS BRIANLIEST

PLZZ HELP

Answer 1

$Given : \sqrt{ \frac{1+sina}{1-sina} }$

$= \ \textgreater \ \sqrt{ \frac{1 + sina}{1-sina} * \frac{1+sina}{1+sina} }$

$= \ \textgreater \ \sqrt{ \frac{(1 + sina)^2}{(1^2 - sin^2a)} }$

$= \ \textgreater \ \sqrt{ \frac{(1 + sina)^2}{cos^2a} }$

$= \ \textgreater \ \frac{1+sina}{cosa}$

$= \ \textgreater \ seca + tana$


Hope this helps!