Question

prove the following trigonometric identitie

Answer 1

Hope it may help you...

Answer 2

Multiply both numerator and denominator by (1+sin A)
we get
√ (1 + sinA) ( 1 + sinA) / (1 - sin A)^2

√ (1 + sinA)^2 / (1 - sin A) (1 + sin A)

√ (1 + sinA)^2 / (1-sin^2A)

√ (1 + sin A )^2 / cos^2 A

= (1 + sin A ) / cos A
= 1 / cosA + sin A / cos A
= sec A + tan A
= RHS
hence proved