Question

Prove the following trigonometric identities
(1-sin²Q) sec²Q=1​

Answer 1

Step-by-step explanation:

LHS. :. (1- sin^2 Q )sec^2Q

cos^2 Q . 1/ cos^2 Q. ( 1- sin^2 Q = cos^2 Q )

(sec^2Q= 1/cos ^2)

and so its 1

therefore , lhs = rhs

as i was solving through phone, that square 2 wasnt coming up so pls manage un understanding