Prove the following trigonometric identities.
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Answer with Step-by-step explanation:
Given : cos²θ/sinθ − cosec θ + sinθ = 0
L.H.S : cos²θ/sinθ − cosec θ + sinθ
= (cos²θ/sinθ − 1/sinθ) + sinθ
[By using the identity, cosecθ = 1/ sinθ]
= (cos²θ − 1)/sinθ + sinθ
= (− sin²θ ) /sinθ + sinθ
[By using the identity, (1- cos²θ) = sin²θ]
= −sinθ + sinθ
= 0
cos²θ/sinθ − cosec θ + sinθ = 0
L.H.S = R.H.S
Hence Proved..
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