prove the following trigonometric identitiy
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Sin∅ - 2Sin³∅ / 2Cos³∅ - Cos∅
= Sin∅ ( 1 - 2Sin²∅ ) / Cos∅ ( 2Cos²∅ - 1 )
= Sin∅ [ 1 - 2 ( 1 - Cos²∅ ) ] / Cos∅ ( 2Cos²∅ - 1 )
= Sin∅ [ 1 - 2 + 2Cos²∅ ] / Cos∅ ( 2Cos²∅ - 1 )
= Sin∅ ( 2Cos²∅ - 1 ) / Cos∅ ( 2Cos²∅ - 1 )
= Sin∅ / Cos∅
= tan∅
♦ Proved ♦
thanks :)
Sin∅ - 2Sin³∅ / 2Cos³∅ - Cos∅
= Sin∅ ( 1 - 2Sin²∅ ) / Cos∅ ( 2Cos²∅ - 1 )
= Sin∅ [ 1 - 2 ( 1 - Cos²∅ ) ] / Cos∅ ( 2Cos²∅ - 1 )
= Sin∅ [ 1 - 2 + 2Cos²∅ ] / Cos∅ ( 2Cos²∅ - 1 )
= Sin∅ ( 2Cos²∅ - 1 ) / Cos∅ ( 2Cos²∅ - 1 )
= Sin∅ / Cos∅
= tan∅
♦ Proved ♦
thanks :)
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