Question

Prove the following trigonometry identities


solve it ​

Answer 1

Answer:

this is the solution... hope it will help you

Answer 2

Step-by-step explanation:

$\huge \red{PROOF}$

L.H.S.=root 1-sin thita/root 1+sin thita

(Rationalizing the denominator)

=root (1-sin thita)^2/root(1-sin^2 thita)

=1-sin thita/root(cos^2thita)

=1-sin thita/cos thita

=1/cos thita-sin thita/cos thita

=sec thita-tan thita

=R.H.S.

L.H.S.=R.H.S.