Prove the followings identities:
(1 + cos θ)(1 – cos θ) = sin2θ
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Answer:
[1+cosФ][1-cosФ]=sin²Ф
1-cosФ+cosФ-cos²Ф=sin²Ф
1-cos²Ф=sin²Ф
∴sin²Ф=sin²Ф
HENCE PROVED
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since sin2(X)= 2sinx.cosx
so
(1+cos(x)) (1-cos(x)) = sin2(x)
we know that. (a+b)(a-b) = a²-b²
using this formula our formula becomes
(1+cos(x)) (1-cos(x)) = 1²-cos²(x)
since we know that 1-cos²(x) = sin²(x)
1²=1
our formula becomes
1-cos²(x)
LHS=RHS
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