Math, asked by nalinitambde611, 2 months ago

Prove the given trigonometric question

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Answered by bewakoofhuinmai
0

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Answered by Anonymous
36

\underline\mathfrak{Answer} \\ LHS =   \frac{ \tan(a) }{( \sec {}^{2} (a)) {}^{2}  }  +  \frac{ \cot(a) }{( \cos\sec {}^{2} (a) ) {}^{2}  }  \\  \\  = \frac{ \frac{ \sin(a) }{ \cos(a) } }{ \frac{1}{ \cos {}^{4} (a) } }  +  \frac{ \frac{ \cos(a) }{ \sin(a) } }{ \frac{1}{ \sin {}^{4} (a) } }  \\ \\  = \sin(a)  \cos {}^{3} (a)  + \cos(a)  \sin {}^{3} (a)   \\  =  \sin(a)  \cos(a)  \:  \:  \:  \\  =  \sin(a)  \cos(a)  = RHS \:

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