Prove the identity (1-tano/1-coto) ^2 = tan^2o
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Answer:
hope it helps and refer to attachment
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Step-by-step explanation:
Answer
1+cot
2
θ
1+tan
2
θ
=
1+
tan
2
θ
1
1+tan
2
θ
(
1−cotθ
1−tanθ
)
2
=
(
tan
2
θ
tan
2
θ+1
)
1+tan
2
θ
=
⎝
⎜
⎜
⎛
1−
tanθ
1
1−tanθ
⎠
⎟
⎟
⎞
2
=tan
2
θ
(tanθ(
tanθ−1
1−tanθ
))
2
=(−tanθ)
2
=tan
2
θ.
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