Prove the identity(a+b) square=a square+2ab+b square with daigram
Answers
Answered by
1
given,
a+bwhole square=(a+b)(a+b)
=a*a+a*b+b*a+b*b
=asquare+2(ab)+bsquare.
hope it helps you.
a+bwhole square=(a+b)(a+b)
=a*a+a*b+b*a+b*b
=asquare+2(ab)+bsquare.
hope it helps you.
Answered by
0
(a+b)square=(a)square+(b)square+2ab
(a+b)*(a+b)=a(a+b)+b(a+b)
(a)square+ab+ab+(b)square
(a)square+(b)square+2ab
Hence Proved
aadiyabanerjee2806:
I HOPE IT WILL HELP YOU
Similar questions