-) Prove the identity:
(cos^2A + tan^2A - 1)/
sin^2A
= tan^2 A
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Acc. To Me,
See Below
By sin²A+cos²A=1
cos²A-1=-sin²A
Put it
(tan²A-sin²A)/sin²A
break tan²A and take sin²A common
sin²A(1/cos²A -1) /sin²A
sin²A will cancel and take LCM
1-cos²A/cos²A
sin²A/cos²A=tan²A
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I hope you understand my answer
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