prove the identity: (cosec theta - cot theta)2=1-costheta/1+costheta
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Answer:
We have,
(cosecθ−cotθ)^ 2
=( 1/ sinθ) − cosθ/sinθ)^2
=( 1-cosθ/sin θ ) ^2
= (1−cosθ) ^2/ sin^2θ
= (1−cosθ)^2/1−cos^2θ
= (1−cosθ)^2/(1+-cosθ)(1+cosθ)
= 1-cosθ/1+cosθ
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