Math, asked by Anjinisharma, 1 year ago

prove the identity ..plz fast

Attachments:

Answers

Answered by rosynegi
2
hey mate ur ans is with this attachment
Attachments:

Anjinisharma: thank you so much
rosynegi: wlc
Answered by manogna1978
1

It is in the form of ( a+b) whole square where it is a2+b2+2ab

So,

Sin2a+cosec2a+2sina.coseca+cos2a+sec2a+2cosa.seca

=1+cosec2a+sec2a+2sina.1÷sina+2cosa÷cosa(sin2a+cos2a=1,coseca=1÷sin,seca=1÷cos)

=5+cosec2a+sec2a

=5+l+cot2a+1+tan2a(cosec2a-cot2a=1,sec2a-tan2a÷1)

=7+tan2a+cot2a

Similar questions