Math, asked by spabronn, 1 year ago

prove the identity secФ² (secФ²-2)+1=tanФ∧4

Answers

Answered by Jahnvi97
2
LHS = secФ² (secФ²-2)+1
RHS =tanФ∧4

LHS=secФ² (secФ²-2)+1
= secФ² (secФ²-1-1)+1
= secФ² (tanФ²-1)+1
=(tanФ²+1)(tanФ²-1)+1
=tanФ^4-1+1
=tanФ^4
= RHS

proved





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