prove the identity sec^2A-tan^2A=1
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1+tan^2=sec^2.
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hope it will help you
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= sec^2 A-tan^2 A=1
Since sec A = 1/cos A and
tan A = sin A/ cos A
=) 1/cos^2 A - sin^2 A/cos^2 A = 1
=) (1-sin^2 A) / cos^2 A = 1
Since sin^2 A + cos^2 A = 1
=) cos^2 A = 1- sin^2 A
=) cos^2 A / cos^2 A = 1
=) 1 = 1
Lhs = Rhs..
Hope it's helpful to u.
Since sec A = 1/cos A and
tan A = sin A/ cos A
=) 1/cos^2 A - sin^2 A/cos^2 A = 1
=) (1-sin^2 A) / cos^2 A = 1
Since sin^2 A + cos^2 A = 1
=) cos^2 A = 1- sin^2 A
=) cos^2 A / cos^2 A = 1
=) 1 = 1
Lhs = Rhs..
Hope it's helpful to u.
donuts13:
thank u
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