prove the irrational number of √3+√5
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Answer:
√3+√5= rational number
(√3+√5)2 = (rational number)2=rational number
(√3)2 + (√5)2 + 2√3√5 = a rational number
3+5+2√15 = is a rational number
8+2√15 = is a rational number
now,
√15 is a irrational no. and 2 is a rational number
2√15 is a irrational no.
but, 8 is a rational number
8+2√15 is a irrational no.
now ,
√3+√5 is a irrational no.
PROVED
shardasahil9525:
shi h ya galat
Answered by
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Let root 3+root5 be rational no.
X=root3+root5
Squaring B.S
X^=( root3+root5)^
X=root3+root5
Squaring B.S
X^=( root3+root5)^
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