Question

Prove the law of conservation of energy by taking the case of a freely falling body.

Answer 1

hey buddy here's ur answer,,,

Law of conservation of energy states that:
Energy can neither be created nor be destroyed. Energy transforms from one form to another form. And, potential energy + kinetic energy = constant
Proof:

At point A,
K.E = 0 m/s
P.E = mgh
P.E = mgh
……....
At point B,
K.E.,
2gh = v2 –u2 (initial velocity = 0 m/s)
2gx = v2 -02
V2 = 2gx
……………
K.E = ½. m.v2
K.E = ½. m. 2gx
K.E = mgx---------------------------- (1)
…………………….
P.E = mgh
P.E = m. g. (h-x)
P.E = mg(h-x)
P.E = mgh – mgx --------------------- (2)
………………………….
From (1) and (2)
K.E + P.E = constant
mgx + mgh – mgx = mgh
mgh = mgh
………………………………………
At point C,
P.E = 0
2gh = v2 - u2 (initial velocity = 0 m/s)
2gh = v2 – 02
2gh = v2
………………………………………………
K.E = ½. m.v
K.E = ½. m. 2gh
K.E = mgh
………………………………………………………..
Thus, in all the points the energy is same.

refer attachment for mor3....

Answer 2

Refer the attachment ❤️