Question

prove the law of conservation of energy for a stone moving vertically down

Answer 1

Suppose a body at its top position has a potential energy 100 and kinetic energy 0and as it comes midway bot becomes half i.e.50 and at last potential energy becomes 0and kinetic energy become 100 so total sum at each point remain constant

Answer 2

Heya...

Here's your answer.........

Let the stone of mass m be at a height h and be dropped from rest at t = 0 sec.

Initial potential energy = PE1 = m g h

initial kinetic energy = 1/2 m 0^2 = 0

Let the stone drop by a distance s in time  t.  As per the laws of kinetics we have

      2 g s = (v^2 - u^2 ) = v^2

Potential energy at time t and height of (h - s) is   PE2 = m g (h - s)

Kinetic energy = KE2 = 1/2 m v^2 = 1/2 m (2 g s) = m g s

Total energy = m g (h - s) + m g s = m g  h

All along the path ,  from t = o to  t = root(2h/g) ,  and height h to 0, the total energy remains as  m g h.

The other forms of energy in the object are assumed to be constant and not varying.

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✨✨✨✨BY BeWaFa ✨✨✨

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Thanks...!!!

XD

Sorry baby 'wink'