Physics, asked by muzammilhasan37, 1 year ago

prove the law of conservation of mechanical energy if the body is thrown with velocity u vertically upward.


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Answers

Answered by wbhat
8
The total energy of any body thrown vertically upward is the sum of the kinetic energy and the potential energy of the body at the height that the body has reached after being thrown vertically upwards.

The’ kinetic energy’ of the body is due to its velocity at any certain point.

And

It's ‘potential energy’ is due to the gravitation potential energy of the body at the height from level at which we consider the potential energy of the body to be 0.

The total energy of the body at any point of time after which it has left our hand is always constant, as it is the sum of the kinetic and potential energy which the body possess.

The potential and the kinetic energy always keeps on changing from the moment the body has left the contact from our hand.

However,

The sum of the two energys adjust in such ways so that to keep the sum constant, and thus the total energy remains constant.

The total energy of the body is equal to the kinetic energy of the body just after it has left the contact of our hand. And this kinetic energy can be calculated by knowing the velocity of the ball,at the moment it leaves contact of the hand.

But,

As the body moves upwards its velocity decreases so the kinetic energy of the body also decreases this decrease in kinetic energy of the body results in increase of potential energy of the body.

And when the body reaches its maximum height its velocity becomes 0,as all of it is converted into potential energy of the body.

Total Energy at the maximum height:

Energy= potential + kinetic

=>mgh+1/2mv2=>mgh+1/2mv2

At maximum height v=0

Therfore which have

ENERGY=mgh

Where h is the maximum height attained by the body.

h, can be found out by the following equation.

h=v2/2gh=v2/2g

Here V=velocity of the body at the moment it leaves our hand.

Energy at any particular height:

Energy=mgh+1/2mv2Energy=mgh+1/2mv2

h=height at which energy to be calculated.

v= velocity of the body at that particular height.
Answered by carrompooltoofan
3

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