Question

· Prove the law of reciprocal proportions from the
following results:
(i) In phosphorus trichloride, P = 22.57%,
Cl = 77.43%
(ii) In hydrogen chloride, H =2.77%; , Cl = 97.23%
(iii) In phosphine, P = 91.18%,H=8.82%​

Answer 1

Answer:

prove the law to answer the question

Explanation:

prove the law of reciprocal proportions from the

following results:

(i) In phosphorus trichloride, P = 22.57%,

Cl = 77.43%

(ii) In hydrogen chloride, H =2.77%; , Cl = 97.23%

(iii) In phosphine, P = 91.18%,H=8.82%​

Answer 2

Answer:

i) In phosphorus chloride,

P = 22.57 %,        Cl = 77.43%

 

ii) In phosphine,

 

P = 91.18%,              H = 8.82%

Thus, ratio of the masses of Cl and H which combine with fixed mass (22.57 parts) of phosphorus separately is,

77.43: 2.18   or   35.5: 1

 

iii) In hydrogen chloride

 

Cl = 97.26%         H = 2.77%

 

Thus, ratio of masses of Cl and H when they combine with each other is

 

97.26: 2.77        or    35.5: 1

 

iv) Ratio 1: Ratio 2 =

This shows a simple whole number ratio.