Prove the mid point theorem analytically
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The line segment joining the midpoints of two sides of a triangle is parallel to the third side and also half of it.
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Hii dear here is your answer ❤️✌️❤️✌️
This answer is verified ✅✅
In ∆AED and CEF ,
AE = CE (given)
/_DAE = /_FCE [ Alternate Interior Angles]
/_AED = /_CEF ( vert.oppo.angles)
∆AED =~∆ CEF
AD = CF and DE = EF (c.p.c.t)
But, AD = BD
BD = CF and BD||CF. (netting DE produced in F)
BCFD is a ||gm.
DF|| BC and DF = BC
DE||BC and DE = 1/2DF = 1/2 BC [ DE = EF]
Hence DE ||BC and DE = 1/2BC..
This answer is verified ✅✅
In ∆AED and CEF ,
AE = CE (given)
/_DAE = /_FCE [ Alternate Interior Angles]
/_AED = /_CEF ( vert.oppo.angles)
∆AED =~∆ CEF
AD = CF and DE = EF (c.p.c.t)
But, AD = BD
BD = CF and BD||CF. (netting DE produced in F)
BCFD is a ||gm.
DF|| BC and DF = BC
DE||BC and DE = 1/2DF = 1/2 BC [ DE = EF]
Hence DE ||BC and DE = 1/2BC..
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