Prove: The opposite angles of a parallelogram are equal.
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Answer:
This proves that opposite angles in any parallelogram are equal. Converse of Theorem 2: If the opposite angles in a quadrilateral are equal, then it is a parallelogram. Given: ∠A=∠C and ∠B=∠D in the quadrilateral ABCD. To Prove: ABCD is a parallelogram.
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Given: A parallelogram ABCD in which AB ║ DC and AD ║ BC.
To Prove : Opposite angles are equal
i.e. ∠A = ∠C and ∠B = ∠D
Construction : Draw diagonal AC
Proof : In ∆ABC and ∆CDA : ∠BAC = ∠DCA [Alternate angles]
∠BCA = ∠DAC [Alternate angles]
AC = AC [Common]
∴ ∆ABC ≅ ∆CDA [By ASA]
⇒ ∠B = ∠D [By cpctc] And, ∠BAD = ∠DCB i.e.,
∠A = ∠C
Similarly,
we can prove that ∠B = ∠D
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