Question

prove the points(1,11),(2,15),(-3,-5) are collinear and find the equation of the straight line containing them​

Answer 1

Step-by-step explanation:

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Answer 2

The equation of the straight line containing the points is

4x - y + 7 = 0.

Given:

The points (1,11),(2,15),(-3,-5)

To Find:

Prove the points are collinear and find the equation of the straight line containing them​.

Solution:

Let  A(1,11), B(2,15), C(-3,-5) be the points.

Slope of AB = (15-11)/(2-1) = 4

Slope of BC = (-5-15)/(-3-2) = 4

Hence, the points  (1,11),(2,15),(-3,-5) are collinear.

Equation of the straight line =

y - 11 = ((15-11)/(2-1))(x-1)

y-11 = 4(x-1)

=> 4x - y + 7 = 0

Hence, the equation of the straight line containing the points is

4x - y + 7 = 0.