Math, asked by salecharamesh6, 11 months ago

Prove the pythagoras the pran class 10

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Answered by DeveshPunjabi17
0

Step-by-step explanation:

your answers

Given: A right-angled triangle ABC.

To Prove- AC² = AB² + BC²

Pythagoras Theorem Proof

Proof: First, we have to drop a perpendicular BD onto the side AC

We know, △ADB ~ △ABC

Therefore, ADAB=ABAC (Condition for similarity)

Or, AB² = AD × AC ……………………………..……..(1)

Also, △BDC ~△ABC

Therefore, CDBC=BCAC (Condition for similarity)

Or, BC²= CD × AC ……………………………………..(2)

Adding the equations (1) and (2) we get,

AB² + BC² = AD × AC + CD × AC

AB² + BC² = AC (AD + CD)

Since, AD + CD = AC

Therefore, AC² = AB² + BC²

Hence, the Pythagorean thoerem is proved.

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Answered by principalajdc
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