Prove the pythagoras the pran class 10
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Given: A right-angled triangle ABC.
To Prove- AC² = AB² + BC²
Pythagoras Theorem Proof
Proof: First, we have to drop a perpendicular BD onto the side AC
We know, △ADB ~ △ABC
Therefore, ADAB=ABAC (Condition for similarity)
Or, AB² = AD × AC ……………………………..……..(1)
Also, △BDC ~△ABC
Therefore, CDBC=BCAC (Condition for similarity)
Or, BC²= CD × AC ……………………………………..(2)
Adding the equations (1) and (2) we get,
AB² + BC² = AD × AC + CD × AC
AB² + BC² = AC (AD + CD)
Since, AD + CD = AC
Therefore, AC² = AB² + BC²
Hence, the Pythagorean thoerem is proved.
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