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we have two circles with a common Centre over line and intersect the outer circle at angle A and D and I'm in a circle at BC to prove that a b is equal to CD let us draw a perpendicular to help for outer circle therefore om perpendicular to altair 4 a.m. is equal to empty mark as it one for the inner circle perpendicular to L now subtracting two from one we have am_bmis equal to Md-mc equal to ab=cd
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Given
a line intersect two concentric circles with centre o at a b c and d
Prove that
AB=CD
according to question
OB+OA=OC+OD
AB = CD
HENCE PROOVED
a line intersect two concentric circles with centre o at a b c and d
Prove that
AB=CD
according to question
OB+OA=OC+OD
AB = CD
HENCE PROOVED
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