Prove the relation f=ma from the second law of motion
rohitkumarabc68:
Dekho yar simple hai we know that f= dp/dt by second law of motion.
Now f=d(m×v)/dt and f=md(v)/dt which is f= m.a(vector) there is your proof hope you find helpful .
Answers
Answered by
3
What is the second law of motion?
If I knew I would have answered
Answered by
5
Let the external force be F, initial velocity be u ,final velocity be v, the time interval be t.
= p1(initial momentum ) = mu
p2(final momentum ) = mv
Therefore, (rate of change of momentum)
Δp=(mv-mu)/t
According to newton’s 2nd law , F ∝ Δp
=F =k*(mv-mu)/t { k is a constant }
In S.I.Units, the value of k is 1
So. F= m(v-u)/t
= F = ma (since v-u/t = a)
Hence proved
Pls mark as Brainliest
Similar questions