Prove the relation s= ut + 1/2 at2
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Consider a velocity-time graph as shown below: The initial velocity u at point A changes at a uniform rate from A to B in time t. BC is the final velocity v in the graph. The time t is represented by OC. The distance travelled by the body is the area under the OABC. Therefore, distance travelled = area of under OABC = area of rectangle OADC + area of triangle ABD Area of rectangle OADC and the area of triangle ABD is given as: Area of rectangle OADC = (OA)(OC) = ut Area of triangle ABD = (½)(area of rectangle AEBD) = ½ at2 Therefore, distance travelled, s = ut + ½ at2Read more on Sarthaks.com - https://www.sarthaks.com/832289/show-by-using-the-graphical-method-that-ut-at-2-where-the-symbols-have-their-usual-meanings
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