Math, asked by sabeenabeegum11, 7 months ago

prove the root 3 is irrational ​

Answers

Answered by Kendreom90
1

Step-by-step explanation:

Suppose The root 3 is a rational number (p, q have no common factor)

squaring by both side

Answered by UNKNOWN3615
0

Step-by-step explanation:

\huge\mathbb\blue{♡Answer♡}

Let us assume to the contrary that √3 is a rational number.

It can be expressed in the form of p/q

where p and q are co-primes and q≠ 0.

⇒ √3 = p/q

⇒ 3 = p2/q2 (Squaring on both the sides)

⇒ 3q² = p²………………………………..(1)

It means that 3 divides p2 and also 3 divides p because each factor should appear two times for the square to exist.

So we have p = 3r

where r is some integer.

⇒ p²= 9r²………………………………..(2)

from equation (1) and (2)

⇒ 3q² = 9r²

⇒ q2= 3r²

Where q² is multiply of 3 and also q is multiple of 3.

Then p, q have a common factor of 3. This runs contrary to their being co-primes. Consequently, p / q is not a rational number. This demonstrates that √3 is an irrational number.

Similar questions