prove the root 3 is irrationl number
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Step-by-step explanation:
let us assume that √3 is a rational number
⇒√3=p/q (where p,q∈positive integers,q≠0 and H.C.F (p,q)=1)
squaring on both sides
⇒3=p²/q²
⇒p²=3q²→equation 1
⇒3 divides p² then 3 divides p
by using euclid algorithm
⇒p=3k
in equation 1
⇒(3k)²=3q²
⇒9k²=3q²
⇒q²=3k²
here 3 divides q² then 3 divides q
∴p,q have common factor 3→equation 2
but p,q have common factor 1
∴this is our contradiction that √3 is a rational number is wrong
∴√3 is an irrational number
hope you understand
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