Question

prove the square of any integer leaves the remainder either 0 or 1 when divided by 4​

Answer 1

Answer:

On My Way

Step-by-step explanation:

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Answer 2

Answer:-

Let the integer be even => x = 2k

x² = (2k)² = 4k²

It is multiple of 4.

Let the integer be odd => y= 2k+1

y² = (2k+1)² = 4k² + 4k + 1 => 4(k² + k) + 1

When it is divided by 4 gives REMAINDER 1.

Hence, proved.