Question

prove the sum of cubes of numbers from 1 to n is equal to (n(n+1)/2) Power raised to 2.

Prove it....​

Answer 1

• $\huge\pink{\mid{\fbox{\tt(answer)}\mid}}$
• You probably mean [n(n+1)/2]^2
• The meaning is, if n is any natural number, then
• 13+23+33+...+n3=[n(n+1)/2]2
• It should actually look like:
• or, a bit more symbolically,
• If you need a proof, the simplest proof is by the method of induction. The derivation of the formula needs a bit more of knowledge than the method of induction. The method of induction is discussed below.
• Let there be some natural number k such that it satisfies the given equation when n=k .
• So the formula stands true when n=k as well as n=k+1 .

Answer 2

Answer:

You probably mean [n(n+1)/2]^2

The meaning is, if n is any natural number, then

13+23+33+...+n3=[n(n+1)/2]2

It should actually look like:

or, a bit more symbolically,

If you need a proof, the simplest proof is by the method of induction. The derivation of the formula needs a bit more of knowledge than the method of induction. The method of induction is discussed below.

Let there be some natural number k such that it satisfies the given equation when n=k .

So the formula stands true when n=k as well as n=k+1 .

Step-by-step explanation:

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