Question

prove the tangents frawn from an external point to a circle are of eqceal length.​

Answer 1

Answer:

To prove : To prove that the tangents drawn from external point are equal.

Construction: Take P as external point and construct tangents as AP and BP

Proof:

ΔAOP and ΔBOP

∠A=∠B (90)

OP common and AO = BO( radii)

By RHS Congruency

ΔAOP≅ΔBOP

By cpct

AP = BP

Answer 2

Answer:

Consider a circle with centre O.

Step-by-step explanation:

Draw two tangent AP and BP on the circle

Join AO and BO.

NOW,

in triangle PAO and triangle PBO,

AO=BO [radii of same circle]

PO is common

OAP = OBP [ angle b/w tangent and radius]

So, By RHS

triangle PAO and triangle PBO are congruent

PA = PB [ CPCT

Hence proved