Prove the theorem the sum of the angles of a quadrilateral is 360° or 4 right angles
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just joined the digonal of quadrilateral and applying angle sum property in both the triangles...
histrionicus:
Above solution is not the solution.
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Concept: The sum of all angles of a triangle = 180°
Consider a quadrilateral PQRS
Construction: Join the diagonal QS
To prove: ∠P + ∠Q + ∠R + ∠S = 360º
Now, we shall Δ PQS and apply angle sum property of triangle.
∠P + ∠PQS + ∠PSQ = 180º --------(i)
Similarly, we shall take Δ QRS and apply angle sum property of triangle.
∠SQR + ∠R + ∠QSR = 180º -----------(ii)
Now, adding equations (i) & (ii)
∠P + ∠PQS + ∠PSQ + ∠SQR + ∠R + ∠QSR = 180º + 180º
or, ∠P + ∠PQS + ∠SQR + ∠R + ∠QSR + ∠PSQ = 360º
or, ∠P + ∠Q + ∠R + ∠S = 360º = 4×90° = 4 right angles
This is the required condition.
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