Physics, asked by Simar111, 1 year ago

Prove the theory of relativity

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Answered by brainiac47
1
looking at a clock, an observer in inertial(i.e., nonaccelerating) motion has a well-defined means of determining which events occur simultaneously with a given event. A second inertial observer, who is in relative motion with respect to the first, however, will disagree with the first observer regarding which events are simultaneous with that given event. (Neither observer is wrong in this determination; rather, their disagreement merely reflects the fact that simultaneityis an observer-dependent notion in relativity.) A notion of simultaneity is required in order to make a comparison of the rates of clocks carried by the two observers. If the first observer’s notion of simultaneity is used, it is found that the second observer’s clock runs slower than the first observer’s by a factor of √((1 − v2/c2)), where v is the relative velocity of the observers and c equals 299,792 km (186,282 miles) per second—i.e., the speed of light. Similarly, using the second observer’s notion of simultaneity, it is found that the first observer’s clock runs slower by the same factor. Thus, each inertial observer determines that all clocks in motion relative to that observer run slower than that observer’s own clock. This should help
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